document.write( "Question 307555: I am having a difficult time translating a word problem into an equation. The question is...\r
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document.write( "Find the measure of an angle such that the difference between the measures of its supplement and three times its complement is 10 degrees.\r
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document.write( "I have tried\r
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document.write( "(x-180)-3(x-90)=10\r
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document.write( "and\r
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document.write( "3(x-90)-(x-180)=10\r
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document.write( "I know that the answer is 50 because it is in the back of the book. Neither one of my equations worked out to be 50, so I know that I must be reading the word problem wrong. I can't figure this out, please help!!! \n" );
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Algebra.Com's Answer #220014 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Find the measure of an angle such that the difference between the measures of its supplement and three times its complement is 10 degrees. \n" ); document.write( ". \n" ); document.write( "Let x = angle \n" ); document.write( "then \n" ); document.write( "complement is 90-x \n" ); document.write( "supplement is 180-x \n" ); document.write( ". \n" ); document.write( "From:\"the difference between the measures of its supplement and three times its complement is 10 degrees\" \n" ); document.write( "(180-x) - 3(90-x) = 10 \n" ); document.write( "180-x - 270+3x = 10 \n" ); document.write( "180 - 270+2x = 10 \n" ); document.write( "-90+2x = 10 \n" ); document.write( "2x = 100 \n" ); document.write( "x = 50 degs\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |