document.write( "Question 307555: I am having a difficult time translating a word problem into an equation. The question is...\r
\n" ); document.write( "\n" ); document.write( "Find the measure of an angle such that the difference between the measures of its supplement and three times its complement is 10 degrees.\r
\n" ); document.write( "\n" ); document.write( "I have tried\r
\n" ); document.write( "\n" ); document.write( "(x-180)-3(x-90)=10\r
\n" ); document.write( "\n" ); document.write( "and\r
\n" ); document.write( "\n" ); document.write( "3(x-90)-(x-180)=10\r
\n" ); document.write( "\n" ); document.write( "I know that the answer is 50 because it is in the back of the book. Neither one of my equations worked out to be 50, so I know that I must be reading the word problem wrong. I can't figure this out, please help!!! \n" ); document.write( "
Algebra.Com's Answer #220013 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Let the angle be A, then its complement is (90-A) and its supplement is (180-A).
\n" ); document.write( "(You have these two backwards!), so...
\n" ); document.write( "(180-A)-3(90-A) = 10 Simplify.
\n" ); document.write( "180-A-270+3A = 10 Combine the A's and the numbers.
\n" ); document.write( "(180-270)+(-A+3A) = 10
\n" ); document.write( "-90+2A = 10 Add 90 to both sides.
\n" ); document.write( "2A = 100 Divide both sides by 2.
\n" ); document.write( "A = 50 degrees.
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