document.write( "Question 307523: solve by factoring: 3x^2-3x=18 \n" ); document.write( "

Algebra.Com's Answer #219999 by Earlsdon(6294) $\"\"$ $\"About$

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Solve by factoring:
\n" ); document.write( " $\"3x%5E2-3x+=+18\"$ First subtract 18 from both sides.
\n" ); document.write( " $\"3x%5E2-3x-18+=+0\"$ Now factor a 3.
\n" ); document.write( " $\"3%28x%5E2-x-6%29+=+0\"$ which means that:
\n" ); document.write( " $\"x%5E2-x-6+=+0\"$ Factor this trinomial.
\n" ); document.write( " $\"%28x-3%29%28x%2B2%29+=+0\"$ Apply the zero product rule: If $\"a%2Ab+=+0\"$ then either $\"a+=+0\"$ or $\"b+=+0\"$ or both.
\n" ); document.write( " $\"x-3+=+0\"$ or $\"x%2B2+=+0\"$ so that...
\n" ); document.write( " $\"highlight%28x+=+3%29\"$ or $\"highlight%28x+=+-2%29\"$ \n" ); document.write( "

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