document.write( "Question 307439: A jet plane flying with the wind flew 2400 miles in 4 hours. Against the wind, the plane flew only 2000 miles in 4 hours. Find the rate of the plane in calm air and the rate of the wind. \n" ); document.write( "
Algebra.Com's Answer #219948 by rapaljer(4671)\"\" \"About 
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Let x = rate of the plane in still air.
\n" ); document.write( "Let y = rate of the wind.\r
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\n" ); document.write( "\n" ); document.write( "\"Rate+=+%28Distance%29%2F%28Time%29\"
\n" ); document.write( "Rate WITH the wind = \"x%2By=2400%2F4\"
\n" ); document.write( "Rate AGAINST the wind = \"x-y=2000%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "x+y=600
\n" ); document.write( "x-y=500\r
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\n" ); document.write( "\n" ); document.write( "Add the equations together:
\n" ); document.write( "2x=1100
\n" ); document.write( "x=550 mph = speed of the plane in still air.\r
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\n" ); document.write( "\n" ); document.write( "Now, x+y=600, where x=550
\n" ); document.write( "550+y=600
\n" ); document.write( "y=50 mph = speed of the wind.\r
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\n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje, Retired
\n" ); document.write( "Seminole State College of Florida
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