document.write( "Question 307439: A jet plane flying with the wind flew 2400 miles in 4 hours. Against the wind, the plane flew only 2000 miles in 4 hours. Find the rate of the plane in calm air and the rate of the wind. \n" ); document.write( "
Algebra.Com's Answer #219948 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! Let x = rate of the plane in still air. \n" ); document.write( "Let y = rate of the wind.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Rate WITH the wind = \n" ); document.write( "Rate AGAINST the wind = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x+y=600 \n" ); document.write( "x-y=500\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add the equations together: \n" ); document.write( "2x=1100 \n" ); document.write( "x=550 mph = speed of the plane in still air.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, x+y=600, where x=550 \n" ); document.write( "550+y=600 \n" ); document.write( "y=50 mph = speed of the wind.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje, Retired \n" ); document.write( "Seminole State College of Florida \n" ); document.write( " |