document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=307395>Question 307395</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many bags with 0.08 cement should mix with 2 bags of 0.63 cement to produce a mix containing 0.19 cement? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #219902 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=219902\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = amount of .08 cement.<BR>\n" );
document.write( "2= amount of .63 cement<BR>\n" );
document.write( "x+2 = amount of .19 cement\r<BR>\n" );
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document.write( "The equation to solve is<BR>\n" );
document.write( ".08x + .63*2= .19(x+2)<BR>\n" );
document.write( ".08x + 1.26 =.19x+.38\r<BR>\n" );
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document.write( "Subtract .08x from each side:<BR>\n" );
document.write( ".08x-.08x + 1.26= .19x-.08x + .38<BR>\n" );
document.write( "1.26=.11x + .38\r<BR>\n" );
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document.write( "Subtract .38 from each side:<BR>\n" );
document.write( "1.26-.38 = .11x+.38-.38<BR>\n" );
document.write( ".88=.11x\r<BR>\n" );
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document.write( "x=.88/.11= 8 bags\r<BR>\n" );
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