document.write( "Question 307391: The stopping distance D of a car after the brakes are applied varies directly as the square of the speed R. If a car traveling 50 mph can stop in 140 ft, how many feet will it take for the same car to stop traveling 90 mph?\r
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document.write( "Please help with this word problem. Thank you. \n" );
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Algebra.Com's Answer #219895 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 50^2/140=90^2/x \n" ); document.write( "50^2x=8,100*140 \n" ); document.write( "2,500x=1,134,000 \n" ); document.write( "x=1,134,000/2,500 \n" ); document.write( "x=453.6 feet. \n" ); document.write( " |