document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=307392>Question 307392</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An alloy of copper is 10% copper and weighs 25 pounds. A second alloy is 18% copper. How much (to the nearest tenth lb.) of the second alloy must be added to the first alloy to get a 13% mixture. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #219894 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=219894\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .10*25+.18x=.13(25+x)<BR>\n" );
document.write( "2.5+.18x=3.25+.13x<BR>\n" );
document.write( ".18x-.13x=4.5-3.25<BR>\n" );
document.write( ".05x=.75<BR>\n" );
document.write( "x=.75/.05<BR>\n" );
document.write( "x=15 pounds of 18% copper is needed.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".10*25+.18*15=.13(25+15)<BR>\n" );
document.write( "2.5+2.7=.13*40<BR>\n" );
document.write( "5.2=5.2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );