document.write( "Question 307378: A jogger runs at an average speed of 5.9mi/hr. If she starts a run at 11:15 am, what time is it after she covers 4.75 x 10^4 ft? \n" ); document.write( "
Algebra.Com's Answer #219893 by rapaljer(4671)\"\" \"About 
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First I would change the rate of 5.9 mi/hr to feet per minute. To do this multiply by 5280 feet per mile, and divide by 60 to change the hours to minutes.\r
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\n" ); document.write( "\n" ); document.write( "Rate = 5.9 * 5280/60= 519.2 feet per minute.\r
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\n" ); document.write( "\n" ); document.write( "Now, the distance to be run is 4.75x10^4 =47500 feet.\r
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\n" ); document.write( "\n" ); document.write( "Use the formula \"d=rt\" to solve for t, \"t=d%2Fr\".
\n" ); document.write( "\"t=+47500%2F519.2=+91.48\" minutes, or 1 hour and 31.48 minutes. \r
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\n" ); document.write( "\n" ); document.write( "Add this to the starting time of 11:15 a.m., and you get
\n" ); document.write( "11:15+ 1:31 = 12:46 p.m. approximately.\r
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\n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje, Retired
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