document.write( "Question 35928: A photo is 3 inches longer that it is wide. A 2-inch border is placed around the photo making the total area of the photo and border 108in2. What are the dimensions of the photo?
\n" ); document.write( " (x-4)(x-10)=108^2
\n" ); document.write( "x^2-44x+ 40=108^2
\n" ); document.write( "x^2-9x-148=0
\n" ); document.write( "(x-13)(x+4)=0
\n" ); document.write( "x>0, so x=13
\n" ); document.write( "x-3=10
\n" ); document.write( "The dimension of the frame is 13*10
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Algebra.Com's Answer #21989 by Prithwis(166)\"\" \"About 
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Let the width be x.
\n" ); document.write( "The length is x+3;
\n" ); document.write( "The length with border is (x+3) + 4 = x+7;
\n" ); document.write( "The width with the border is x+4
\n" ); document.write( "Area = 108
\n" ); document.write( "(x+7)(x+4) = 108
\n" ); document.write( "=> x^2+11x-80 = 0
\n" ); document.write( "=> (x+16)(x-5) = 0
\n" ); document.write( "=> x = 5; (can't be -ve)
\n" ); document.write( "The dimension of the photo is 8 inch X 5 inch
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