document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=307362>Question 307362</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am REALLY struggling with this one. \r<BR>\n" );
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document.write( "You mix your own feed for the puppies. The feed mix consists of ground meat and ground grains. You mix a total of 100 pounds at a time. The ground meat is 45% protein and the ground grains is 18% protein, find the amount of ground meat and ground grains required for a 100 pound feed mix at the optimum protein level of 28%. Solve this system using the Elimination Method.  Round solutions to nearest whole number. The system of equations that I thought should be used is: m + g = 100  and  0.45m + 0.18g = 0.28 but I cannot come up with a sensible solution. Please help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #219881 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=219881\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  The feed mix consists of ground meat and ground grains.<BR>\n" );
document.write( " You mix a total of 100 pounds at a time. The ground meat is 45% protein and the<BR>\n" );
document.write( " ground grains is 18% protein, find the amount of ground meat and ground grains<BR>\n" );
document.write( " required for a 100 pound feed mix at the optimum protein level of 28%. <BR>\n" );
document.write( "Solve this system using the Elimination Method. <BR>\n" );
document.write( "Round solutions to nearest whole number.<BR>\n" );
document.write( " The system of equations that I thought should be used is: m + g = 100 and 0.45m + 0.18g = 0.28<BR>\n" );
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document.write( "You are so close:<BR>\n" );
document.write( "the 2nd equation should be .45m + .18g = .28(100)<BR>\n" );
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document.write( "Multiply the 1st equation by .18 subtract from the above equation<BR>\n" );
document.write( ".45m + .18g = .28(100)<BR>\n" );
document.write( ".18m + .18g = .18(100)<BR>\n" );
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document.write( ".45m + .18g = 28<BR>\n" );
document.write( ".18m + .18g = 18<BR>\n" );
document.write( "----------------- subtraction eliminates g, find m<BR>\n" );
document.write( ".27m = 10<BR>\n" );
document.write( "m = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10%2F.27 ALIGN=MIDDLE  ALT=\"10%2F.27\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "m = 37 lb of meat<BR>\n" );
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document.write( "Find grain<BR>\n" );
document.write( "37 + g = 100<BR>\n" );
document.write( "g = 100 - 37<BR>\n" );
document.write( "g = 63 lb of grain<BR>\n" );
document.write( ";<BR>\n" );
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document.write( "Check solution in the % equation<BR>\n" );
document.write( ".45(37) + .18(63) = .28(100)<BR>\n" );
document.write( "16.65 + 11.34 = 27.99 ~ 28 </SPAN>\n" );
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