document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=35929>Question 35929</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular parking lot is 50 ft longer than it is wide. Determine the dimensions of the parking lot if it measures 250 ft diagonally.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #21988 by </B><A HREF=/tutors/aboutme.mpl?userid=Prithwis><B>Prithwis(166)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Prithwis><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.nriassociation.com/BeliveITorNOT/mittal70millionHouse.jpg valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=21988\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the width be x ft.<BR>\n" );
document.write( "The length is x+50 ft.<BR>\n" );
document.write( "The length of the diagonal is sqrt [(x^2) + (x+50)^2] ft;<BR>\n" );
document.write( "[(x^2) + (x+50)^2] = 250^2<BR>\n" );
document.write( "=> x^2 + (x+50)^2 = 62500<BR>\n" );
document.write( "=> x^2 + x^2 + 100x + 2500 = 62500<BR>\n" );
document.write( "=> x^2 + 50x - 30000 = 0<BR>\n" );
document.write( "=> x = [-50 + sqrt(2500+120000)]/2 because x cannot be negative<BR>\n" );
document.write( "=> x = [-50 + sqrt(122500)]/2<BR>\n" );
document.write( "=> x = (-50+350)/2 = 150;<BR>\n" );
document.write( "The Dimension of the parking lot is 200 ft X 150 ft </SPAN>\n" );
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