document.write( "Question 307359: trains A and B are traveling in in the same direction on parallel tracks. train A is traveling at 80 miles per hour and train B is traveling at 100 miles per hour. train A passes a station at 6:10 A.M. If train B passes the same station at 6:25 A.M., at what time will train B catch up to train A? \n" ); document.write( "
Algebra.Com's Answer #219878 by ankor@dixie-net.com(22740)\"\" \"About 
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trains A and B are traveling in in the same direction on parallel tracks. train A is traveling at 80 miles per hour and train B is traveling at 100 miles per hour. train A passes a station at 6:10 A.M. If train B passes the same station at 6:25 A.M., at what time will train B catch up to train A?
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\n" ); document.write( "from the given information, we know that train B is 15 min (1/4 hr) behind
\n" ); document.write( " train A, when train A passes the station
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\n" ); document.write( "The distance between the trains at this time: \"1%2F4\" * 100 = 25 mi
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\n" ); document.write( "Let t = time required for train B to catch train A
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\n" ); document.write( "write a distance equation: Dist = speed * time
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\n" ); document.write( "Train B travel dist = Train A travel dist + 25 mi
\n" ); document.write( "100t = 80t + 25
\n" ); document.write( "100t - 80t = 25
\n" ); document.write( "20t = 25
\n" ); document.write( "t = \"25%2F20\"
\n" ); document.write( "t = 1.25 or 1 hr 15 min
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\n" ); document.write( "6:10 + 1:15 = 7:25 AM, B catches A \n" ); document.write( "
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