document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=307256>Question 307256</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 mph and starts 3 hours after the first cyclist who is traveling at 6 mph. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?\r<BR>\n" );
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document.write( "Not sure if this is Combinatorics, but help is appreciated :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #219868 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=219868\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "D=6T<BR>\n" );
document.write( "D=10(T-3)<BR>\n" );
document.write( "THE 2 DISTANCES ARE EQUAL.<BR>\n" );
document.write( "6T=10(T-3)<BR>\n" );
document.write( "6T=10T-30<BR>\n" );
document.write( "6T-10T=-30<BR>\n" );
document.write( "-4T=-30<BR>\n" );
document.write( "T=-30/-4<BR>\n" );
document.write( "T=7.5 HOURS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "6*7.5=10(7.5-3)<BR>\n" );
document.write( "45=1-*4.5<BR>\n" );
document.write( "45=45<BR>\n" );
document.write( "7.5-3=4.5 HOURS AFTER THE SECOND RIDER LEAVES THEY WILL MEET. </SPAN>\n" );
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