document.write( "Question 307270: If (y -3)^2 = 16, what is the smallest possible value of y^2?
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Algebra.Com's Answer #219843 by Theo(13342)![]() ![]() You can put this solution on YOUR website! (y-3)^2 = 16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Take square root of both sides of the equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y-3 = 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add 3 to both sides of the equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = 7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The only value that y can be is 7.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There is no other value of y that would satisfy this equation which is why I wonder why you asked for the smallest value of y.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substitute for 7 in the original equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(7-3)^2 = 16 which becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4^2 = 16 which becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "16 = 16 which is true, confirming that y = 7 is the correct value to satisfy the equation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If this was an inequality, such as:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(y-3)^2 >= 16, then you might ask for the smallest value of y.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You would solve the inequality pretty much the way you would solve the equality.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Take the square root of both sides of this equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y-3 >= 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add 3 to both sides of this equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y >= 7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The smallest value y could be then would be 7.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you had the inequality equation of:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(y-3)^2 > 16, then you would solve again using the same method.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Take the square root of both sides of the equation to getr:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y-3 > 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add 3 to both sides of the equation to get y > 7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "then the smallest value that y could be would be something greater than 7.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you were looking for integers, it would be 8.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you allowed real numbers than it could be anything as long as it was grater than 7.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "7.01, 7.001, 7.0001, 7.000001, etc.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |