document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=307253>Question 307253</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (2n)/(1-n) + (n+3)/(n2-1)<BR>\n" );
document.write( "how t o solve this? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #219839 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=219839\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (2n)/(1-n) + (n+3)/(n2-1)\r<BR>\n" );
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document.write( "2n/ -1(n-1) +(n+3)/ (n+1)(n-1)\r<BR>\n" );
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document.write( "-2n/ (n-1) + n+3 / (n+1)(n-1)\r<BR>\n" );
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document.write( "(n+1)(n-1) is the LCM\r<BR>\n" );
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document.write( "-2n(n+1) +(n+3) / (n+1)(n-1)\r<BR>\n" );
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document.write( "-2n^2-2n +n+3 / (n+1)(n-1)\r<BR>\n" );
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document.write( "-2n^2-n+3 / (n+1)(n-1) \r<BR>\n" );
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document.write( "-1(2n^2+n-3)/ (n+1)(n-1)\r<BR>\n" );
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document.write( "-1(2n^2+3n-2n-3)/(n+1)(n-1)\r<BR>\n" );
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document.write( "-1{n(2n+3)-1(2n+3)}/(n+1)(n-1)\r<BR>\n" );
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document.write( "-1(n-1)(2n+3) / (n+1)(n-1)<BR>\n" );
document.write( "-(2n+3)/n+1)\r<BR>\n" );
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document.write( "-\r<BR>\n" );
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document.write( "-\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );