document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=307214>Question 307214</A>: <I><SPAN STYLE=\"word-break: break-all;\"> steve is 5 times as as old as janice in 12 years she will be twice as old as she was then, how old are they now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #219838 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=219838\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> steve is 5 times as as old as janice in 12 years he will be twice as old as she was then, how old are they now\r<BR>\n" );
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document.write( "I have corrected the sum . I do not know if the correction is OK.\r<BR>\n" );
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document.write( "let janice be x years now\r<BR>\n" );
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document.write( "steve will be5x\r<BR>\n" );
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document.write( "after 12 years <BR>\n" );
document.write( "5x +12 = 2(2x+12)\r<BR>\n" );
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document.write( "5x+12 =  4x +24\r<BR>\n" );
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document.write( "5x-4x= 24-12\r<BR>\n" );
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document.write( "x=12 janice's age now\r<BR>\n" );
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document.write( "Steve's age will be 12* 5=60 years </SPAN>\n" );
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