document.write( "Question 307069: A certian plane can travel 1500 miles in 5 hours when flying into the wind. The same plane can travel 2000 miles in 5 hours when flying with the wind. Find the rate of the wind. \n" ); document.write( "

Algebra.Com's Answer #219815 by mananth(16946) $\"\"$ $\"About$

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A certian plane can travel 1500 miles in 5 hours when flying into the wind. The same plane can travel 2000 miles in 5 hours when flying with the wind. Find the rate of the wind.\r
\n" ); document.write( "\n" ); document.write( "let speed of wind be xmph
\n" ); document.write( "speed of plane in still air be y\r
\n" ); document.write( "\n" ); document.write( "distance = rate * time
\n" ); document.write( "1500 = 5(y-x)
\n" ); document.write( "similarly 2000 = 5(y+x)\r
\n" ); document.write( "\n" ); document.write( "1500 = 5y-5x
\n" ); document.write( "2000 = 5y+5x\r
\n" ); document.write( "\n" ); document.write( "Add the two equations\r
\n" ); document.write( "\n" ); document.write( "weget 10 y= 3500\r
\n" ); document.write( "\n" ); document.write( "y= 350 mph
\n" ); document.write( ".
\n" ); document.write( "1500 = 5y-5x
\n" ); document.write( "plug the value of y in the equation\r
\n" ); document.write( "\n" ); document.write( "1500 = 1750-5x\r
\n" ); document.write( "\n" ); document.write( "-5x= -250
\n" ); document.write( "x= 50 mph the speed of the wind\r
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