document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=35893>Question 35893</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For security reasons, a company is planning to enclose a rectangular area of 11200 sq.m in the rear of its factory.one side will be bounded by the building aand the other sides will be fenced If 300m of fencing be used what will be the dimensions  of the rectangular area.\r<BR>\n" );
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document.write( "answer: let L be the length and Bbe the breadth of the rectangular area.<BR>\n" );
document.write( "hence Area = L times B = 11200.\r<BR>\n" );
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document.write( "Perimeter= 2((L+B)<BR>\n" );
document.write( "ONE SID IS BOUNDED BY THE FACTORY HENCE, 300= 2L+B. i can't solve the quadratic eqn<BR>\n" );
document.write( "hence    300 = 2L + (11200/L)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #21979 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=21979\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the fencing is 300 which is the perimeter<BR>\n" );
document.write( "so:<BR>\n" );
document.write( "l+2w=300<BR>\n" );
document.write( "l=300-2w (subsituton)<BR>\n" );
document.write( "Area is 11200<BR>\n" );
document.write( "So:<BR>\n" );
document.write( "(300-2w)(w)=11200<BR>\n" );
document.write( "-2w^2+300w-11200=0<BR>\n" );
document.write( "w^2-150w+5600=0<BR>\n" );
document.write( "Can you solve form there?<BR>\n" );
document.write( "you get w=80<BR>\n" );
document.write( "and l=140\r<BR>\n" );
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document.write( "Paul. </SPAN>\n" );
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