document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=307169>Question 307169</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the perimeter of a rectangle that has an area of 12,150 square feet?  the ratio of length to width is 3:2. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #219786 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=219786\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> what is the perimeter of a rectangle that has an area of 12,150 square feet? the ratio of length to width is 3:2.\r<BR>\n" );
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document.write( "Let the two sides of the rectangle be 3x and 2x respectively. Then we have:\r<BR>\n" );
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document.write( "3x*2x = 12150<BR>\n" );
document.write( "6x^2 = 12150<BR>\n" );
document.write( "x^2 = 2025<BR>\n" );
document.write( "x = 45\r<BR>\n" );
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document.write( "The two sides then are 2*45 = 90 and 3*45 = 135 </SPAN>\n" );
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