document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=35895>Question 35895</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This problem is from a worksheet. Find all zeros of each function. If a zero has a multiplicity greater than on, please note the multiplicity.<BR>\n" );
document.write( "f(x)= x^3+12^2-16\r<BR>\n" );
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document.write( "I have tried to solve using synthetic division, but cannot find a number that makes it zero, I have tried +-{1,2,4,8,16} and I put a zero in place where there is a missing degree...but still cannot find answer. My p/q is probably wrong, but I am pulling my hair out here trying to figure it out. Thanks for the help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #21978 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=21978\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This problem is from a worksheet. Find all zeros of each function. If a zero has a multiplicity greater than on, please note the multiplicity.<BR>\n" );
document.write( "f(x)= x^3+12x^2-16...I THINK IT IS 12X^2..OK?<BR>\n" );
document.write( "I have tried to solve using synthetic division, but cannot find a number that makes it zero, I have tried +-{1,2,4,8,16} and I put a zero in place where there is a missing degree...but still cannot find answer. My p/q is probably wrong, but I am pulling my hair out here trying to figure it out. Thanks for the help.<BR>\n" );
document.write( "NOTHING WRONG WITH YOU.YOU ARE CORRECT.IT HAS A ROOT WHICH IS NOT RATIONAL.HENCE YOU ARE NOT GETTING THE ANSWER BY TRYING 1,2,4,8,16...<BR>\n" );
document.write( "THE ROOT IS ABOUT 1.1 APPROXIMATELY.I AM NOT SURE WHICH METHODS YOU HAVE BEEN TAUGHT ,WHEN THE CUBIC HAS AN IRRATIONAL ROOT .JUST GIVE ME YOUR BACK GROUND AND I SHALL TRY TO HELP.ONE EASY WAY IS TO SOLVE GRPHICALY.THAT IS DRAW A GRAPH FOR Y=X^3 AND ANOTHER GRAPH FOR Y=16-12X^2 AND FIND THE POINT OF INTERSECTION. </SPAN>\n" );
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