document.write( "Question 35900: Translate the following into a quadratic equation, and solve it:
\n" ); document.write( "The length of a rectangular garden is three times its width; if the area of the garden is 75 square meters, what are its dimensions?
\n" ); document.write( "

Algebra.Com's Answer #21977 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Start with the formula for the area of a rectangle:\"A+=+L%2AW\"
\n" ); document.write( "In your problem, L = 3W...substitute this into the basic formula.
\n" ); document.write( "\"A+=+%283W%29%2AW\"
\n" ); document.write( "\"A+=+3W%5E2\" But the area (A) is given as 75 square meters.
\n" ); document.write( "\"75+=+3W%5E2\" Subtract 75 from both sides.
\n" ); document.write( "\"3W%5E2-75+=+0\" There's the quadratic equation.
\n" ); document.write( "To solve, factor out a 3.
\n" ); document.write( "\"3%28W%5E2-25%29+=+0\"Apply the zero products principle.
\n" ); document.write( "\"W%5E2-25+=+0\" Solve by factoring.
\n" ); document.write( "\"%28W-5%29%28W%2B5%29+=+0\" Apply the zero products principle.
\n" ); document.write( "\"W-5+=+0\" and/or \"W%2B5+=+0\"
\n" ); document.write( "If \"W-5+=+0\" then \"W+=+5\" This is an acceptable solution since W is positive.
\n" ); document.write( "If \"W%2B5+=+0\" then \"W+=+-5\" This is not meaningful as the width, W, must be a positive value.\r
\n" ); document.write( "\n" ); document.write( "The width (W) is 5 meters.
\n" ); document.write( "The length (L) is 3W = 3(5) = 15 meters.
\n" ); document.write( "
\n" );