document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=307082>Question 307082</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve the cuberoot of 4 divided by the 5th root of 8?\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #219739 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=219739\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do you solve the cuberoot of 4 divided by the 5th root of 8? <BR>\n" );
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document.write( "convert to exponent form<BR>\n" );
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document.write( "4^(1/3) <BR>\n" );
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document.write( "8^(1/5)<BR>\n" );
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document.write( "4 = 2^2 and 8 = 2^3, therefore we can write this as:<BR>\n" );
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document.write( "2^(2/3) <BR>\n" );
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document.write( "2^(3/5)<BR>\n" );
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document.write( "like terms so we can combine the exponents;<BR>\n" );
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document.write( "2^(2/3 - 3/5) = 2^(10/15 - 9/15) = 2^(1/15) </SPAN>\n" );
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