document.write( "Question 306948: the measure of a supplement of an angle is 12 degrees greater than three times the measure of a complement. Find the measure of the angle. Thank you so much! :D \n" ); document.write( "
Algebra.Com's Answer #219732 by ankor@dixie-net.com(22740)\"\" \"About 
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he measure of a supplement of an angle is 12 degrees greater than three times the measure of a complement. Find the measure of the angle.
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\n" ); document.write( "Let x = the unknown angle
\n" ); document.write( "then we know:
\n" ); document.write( "180 - x = the supplement
\n" ); document.write( "and
\n" ); document.write( "90 - x = the complement
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\n" ); document.write( "Write an equation for the statement:
\n" ); document.write( "The measure of a supplement of an angle is 12 degrees greater than three times the measure of a complement.\"
\n" ); document.write( "180 - x = 3(90-x) + 12
\n" ); document.write( "180 - x = 270 - 3x + 12
\n" ); document.write( "-x + 3x = 270 + 12 - 180
\n" ); document.write( "2x = 102
\n" ); document.write( "x = \"102%2F2\"
\n" ); document.write( "x = 51 degrees is the angle
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\n" ); document.write( "See if that is true in the statement\"
\n" ); document.write( "\"measure of a supplement of an angle is 12 degrees greater than three times the measure of a complement.\"
\n" ); document.write( "180 - 51 = 3(90-51) + 12
\n" ); document.write( "129 = 3(39) + 12
\n" ); document.write( "129 = 117 + 12\r
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