document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=307107>Question 307107</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Fifteen more than twice the hours Carla worked last week is the same as three times the hours she worked this week decreased by fifteen. She worked the same number of hours each week. How many hours did she work each week? \r<BR>\n" );
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document.write( " - i came up with the equation : 2c+15=3c-15, then i subtracted 2c from each side which is now 15=c-15. but now im stuck. please help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #219720 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=219720\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 15 = c - 15<BR>\n" );
document.write( "Add 15 to both sides<BR>\n" );
document.write( "15 + 15 = c<BR>\n" );
document.write( "c = 30<BR>\n" );
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document.write( "Check in your original equation:<BR>\n" );
document.write( " 2(30) + 15 = 3(30) - 15<BR>\n" );
document.write( "75 = 75 </SPAN>\n" );
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