document.write( "Question 306997: i need your help on logarithm, please. how do you find out the solution of the problem if it has a coefficient and an exponent? ex: 5log6^(x+1)=5
\n" ); document.write( "are you supposed to divide by 5 because of the coefficient? how do i figure this problem out?
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Algebra.Com's Answer #219694 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
\"5log%286%5E%28x%2B1%29%29=+5\"
\n" ); document.write( "Write it using the log equiv of exponents
\n" ); document.write( "\"5%28x%2B1%29log%286%29=+5\"
\n" ); document.write( "divide both sides by the log(6)
\n" ); document.write( "5(x+1) = \"5%2Flog%286%29\"
\n" ); document.write( "using a calc
\n" ); document.write( "5(x+1) = 6.425486
\n" ); document.write( ":
\n" ); document.write( "5x + 5 = 6.425486
\n" ); document.write( ":
\n" ); document.write( "5x = 6.425486 - 5
\n" ); document.write( ":
\n" ); document.write( "5x = 1.425486
\n" ); document.write( "x = \"1.425486%2F5\"
\n" ); document.write( "x = .2851
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check on a calc: enter 5*log(6^(.2851+1)) = . 5.000
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