document.write( "Question 307008: I cannot figure this out it's stressing me out.....I hope u can help me. PLEASE
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document.write( "16y^2-9x^2+36x-32y-164=0 I need to know the coordinates, and if its hyperbolic(center and focci) circular (center and vertex) elliptical(center and focci) parabolic(vertex and focus). Please please explain. Thank you \n" );
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Algebra.Com's Answer #219669 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! this is a hyperbola (second order terms, squares, have different signs)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "isolating the squares will make it more recognizable\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "16y^2 - 32y + 16 - 9x^2 + 36x - 36 - 144 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "16(y - 1)^2 - 9(x - 2)^2 = 144\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "{[(y - 1)^2] / 9} - {[(x - 2)^2] / 16} = 1 \n" ); document.write( " |