document.write( "Question 307051: Students received an A in math class. 2 used in person tutors. 4 used on line tutors. 5 used no tutors.\r
\n" ); document.write( "\n" ); document.write( "Students did not receive A in the math class. 34 used in person tutors, 53 used on line students. 20 used no students.\r
\n" ); document.write( "\n" ); document.write( "If the student from the whole group were randomly chose, what is the probability that the student use in person or on line tutors?\r
\n" ); document.write( "\n" ); document.write( "I think this is an addition rule.
\n" ); document.write( "P (A or B)= P(A) + P (B)-P (A-B)\r
\n" ); document.write( "\n" ); document.write( "36/118+ 57/118 - (93/118) = 0.000455\r
\n" ); document.write( "\n" ); document.write( "Thank you \n" ); document.write( "

Algebra.Com's Answer #219665 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
You are on the right track, but the third fraction is not $\"93%2F118\"$ . First off, notice how $\"36%2B57=93\"$ , so this would mean that the three fractions would combine to 0, which is not what we're looking for.\r
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\n" ); document.write( "\n" ); document.write( "Instead, the third fraction is the product of the two first fraction. \n" ); document.write( "

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