document.write( "Question 307008: I cannot figure this out it's stressing me out.....I hope u can help me. PLEASE
\n" ); document.write( "16y^2-9x^2+36x-32y-164=0 I need to know the coordinates, and if its hyperbolic(center and focci) circular (center and vertex) elliptical(center and focci) parabolic(vertex and focus). Please please explain. Thank you
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Algebra.Com's Answer #219662 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
You need to complete the square in x and y.
\n" ); document.write( "\"+16y%5E2-9x%5E2%2B36x-32y-164=0\"
\n" ); document.write( "\"-9x%5E2%2B36x%2B16y%5E2-32y-164=0\"
\n" ); document.write( "\"-9%28x%5E2-4x%29%2B16%28y%5E2-2y%29=164\"
\n" ); document.write( "\"-9%28x%5E2-4x%2B4%29%2B16%28y%5E2-2y%2B1%29=164-36%2B16\"
\n" ); document.write( "\"-9%28x-2%29%5E2%2B16%28y-1%29%5E2=144\"
\n" ); document.write( "\"%28y-1%29%5E2%2F9-%28x-2%29%5E2%2F16=1+\"
\n" ); document.write( "Unequal coefficients for \"x%5E2\" and \"y%5E2\" and unequal signs are the signs of a hyperbola.
\n" ); document.write( "There now you can solve for center and foci.
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