document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=307040>Question 307040</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Anne purchased a new truck for $16,500. She sold it 6 years later for $3,700. Find the annual rate of depreciation on the truck.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #219656 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=219656\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, take the difference of the two values to get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=16500-3700=12800 ALIGN=MIDDLE  ALT=\"16500-3700=12800\"   DISABLED_style= \"max-width:90%; height:auto;\" >. This means that over 6 years, the truck has lost $12,800 in value. Now just divide this number by 6 to find the annual rate of depreciation: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12800%2F6=2133.33333 ALIGN=MIDDLE  ALT=\"12800%2F6=2133.33333\"   DISABLED_style= \"max-width:90%; height:auto;\" > and round to the nearest penny to get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2133.33 ALIGN=MIDDLE  ALT=\"2133.33\"   DISABLED_style= \"max-width:90%; height:auto;\" >. So the truck has lost about $2133.33 per year. </SPAN>\n" );
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