document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=307041>Question 307041</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The half-life of C-12 is about 3,700 years. How long will it be before a 2.35g sample of C-12 decays to 1.46g of C-12?\r<BR>\n" );
document.write( "\n" );
document.write( "I have no clue...please help.<BR>\n" );
document.write( "Thank You </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #219649 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=219649\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the half-life equation for this situation is ___ 1.46 = 2.35 (1/2)^(t / 3700) ___ where \"t\" is the decay time in years\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "use logs to solve for \"t\" </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );