document.write( "Question 307032: Use the change base formula to solve the equation.\r
\n" ); document.write( "\n" ); document.write( "2^x = 5
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Algebra.Com's Answer #219646 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
By base change formula, do you mean
\n" ); document.write( "\"y%5Ex=+a\" is equivalent to \"x=+%28log+a%29%2F%28log+y%29+\"???\r
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\n" ); document.write( "\n" ); document.write( "If so, then
\n" ); document.write( "\"2%5Ex=5\" is equivalent to \"x=+%28log+5%29%2F%28log+2%29+\", which by calculator is about 2.32.\r
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\n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje, Retired
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