document.write( "Question 306953: what is the solution for x in absolute value of 3x-3 =5 \n" ); document.write( "
Algebra.Com's Answer #219641 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"abs%283x-3%29=5\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "Break up the absolute value (remember, if you have \"abs%28x%29=a\", then \"x=-a\" or \"x=a\")\r
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\n" ); document.write( "\n" ); document.write( "\"3x-3=-5\" or \"3x-3=5\" Set the expression \"3x-3\" equal to the original value 5 and it's opposite -5\r
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\n" ); document.write( "\n" ); document.write( "Now lets focus on the first equation \"3x-3=-5\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x=-5%2B3\"Add 3 to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"3x=-2\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-2%29%2F%283%29\" Divide both sides by 3 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=-2%2F3\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "Now lets focus on the second equation \"3x-3=5\"\r
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\n" ); document.write( "\n" ); document.write( "\"3x=5%2B3\"Add 3 to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"3x=8\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x=%288%29%2F%283%29\" Divide both sides by 3 to isolate x\r
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\n" ); document.write( "\n" ); document.write( "\"x=8%2F3\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=-2%2F3\" or \"x=8%2F3\"
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