document.write( "Question 306999: Solution X is 40% acid and solution Y is 85% acid. How much of each is needed to make a 90 Liters of a solution that is 70% acid? \n" ); document.write( "
Algebra.Com's Answer #219629 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Solution X is 40% acid and solution Y is 85% acid. How much of each is needed to make a 90 Liters of a solution that is 70% acid?\r \n" ); document.write( "\n" ); document.write( "solution X - 40% \n" ); document.write( "solution y -85%\r \n" ); document.write( "\n" ); document.write( "Let quantity of X be x liters \n" ); document.write( "Quantity of Y will be 90-x liters\r \n" ); document.write( "\n" ); document.write( "Total quantity required = x+90 with cocentration of 70%\r \n" ); document.write( "\n" ); document.write( "Concentration of X in the mixture = 0.4x \n" ); document.write( "Concentration of Y in the mixture = 0.85(90-x) \n" ); document.write( "Concentration of mix= 0.7(90+x)\r \n" ); document.write( "\n" ); document.write( "0.4x+0.85(90-x)= 0.7(x+90)\r \n" ); document.write( "\n" ); document.write( "0.4x+76.5-0.85x = 0.7x+63\r \n" ); document.write( "\n" ); document.write( "-1.15x=-13.5\r \n" ); document.write( "\n" ); document.write( "x=11.7 liters \n" ); document.write( "Balance will be solution Y=9.3 liters\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |