document.write( "Question 306973: A rectangle is 4 times as long as it is wide. A second rectangle is 5 centimeter longer and 2 centimeters wider than the first. The area of the second rectangle is 530 square centimeters greater than the first. What are the dimensions of the original rectangle? \n" ); document.write( "
Algebra.Com's Answer #219603 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let the width of the rectangle be x\r \n" ); document.write( "\n" ); document.write( "the length will be 4x \n" ); document.write( ".\r \n" ); document.write( "\n" ); document.write( "second rectangle\r \n" ); document.write( "\n" ); document.write( "Width will be x+2\r \n" ); document.write( "\n" ); document.write( "Length will be 4x+5\r \n" ); document.write( "\n" ); document.write( "(4x+5)(x+2)-530=4x*x\r \n" ); document.write( "\n" ); document.write( "4x^2+13x+10-530=4x^2\r \n" ); document.write( "\n" ); document.write( "13x=520\r \n" ); document.write( "\n" ); document.write( "x=40 cm which is the width\r \n" ); document.write( "\n" ); document.write( "length = 4x \n" ); document.write( "=160 cm.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |