document.write( "Question 306973: A rectangle is 4 times as long as it is wide. A second rectangle is 5 centimeter longer and 2 centimeters wider than the first. The area of the second rectangle is 530 square centimeters greater than the first. What are the dimensions of the original rectangle? \n" ); document.write( "
Algebra.Com's Answer #219603 by mananth(16946)\"\" \"About 
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let the width of the rectangle be x\r
\n" ); document.write( "\n" ); document.write( "the length will be 4x
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\n" ); document.write( "\n" ); document.write( "second rectangle\r
\n" ); document.write( "\n" ); document.write( "Width will be x+2\r
\n" ); document.write( "\n" ); document.write( "Length will be 4x+5\r
\n" ); document.write( "\n" ); document.write( "(4x+5)(x+2)-530=4x*x\r
\n" ); document.write( "\n" ); document.write( "4x^2+13x+10-530=4x^2\r
\n" ); document.write( "\n" ); document.write( "13x=520\r
\n" ); document.write( "\n" ); document.write( "x=40 cm which is the width\r
\n" ); document.write( "\n" ); document.write( "length = 4x
\n" ); document.write( "=160 cm.\r
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