document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=306913>Question 306913</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A grocer at a specialty store is mixing coffee worth $6 per pound with coffee worth $8 per pound. He wants to obtain 144 pounds of coffee worth $7.50 per pound.How much of each coffee should he use?\r<BR>\n" );
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document.write( "Amount of coffee X=108<BR>\n" );
document.write( "Amount of coffee Y=36 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #219569 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=219569\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8x+6(144-x)=7.50*144<BR>\n" );
document.write( "8x+864-6x=1,080<BR>\n" );
document.write( "2x=1,080-864<BR>\n" );
document.write( "2x=215<BR>\n" );
document.write( "x=216/2<BR>\n" );
document.write( "x=108 pounds of $8 coffee is uded.<BR>\n" );
document.write( "144-108=36 pounds of $6 coffee is used.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "8*108+6*36=7.50*144<BR>\n" );
document.write( "864+216=1,080<BR>\n" );
document.write( "1,080=1,080\r<BR>\n" );
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document.write( " </SPAN>\n" );
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