document.write( "Question 306868: Each set of three points is collinear. Find each missing x- or y-value. Enter each answer to the nearest hundredth.
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\n" ); document.write( "(6, 10.2), (1.5, 3.45), (x, 2.85) \n" ); document.write( "
Algebra.Com's Answer #219554 by dabanfield(803)\"\" \"About 
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(6, 10.2), (1.5, 3.45), (x, 2.85)\r
\n" ); document.write( "\n" ); document.write( "The slope-intercept form of a line is:\r
\n" ); document.write( "\n" ); document.write( "y = m*x + b where m is the slope and b is the value of y where the line crosses the x-axis (that is when x = 0 ).\r
\n" ); document.write( "\n" ); document.write( "m = (10.2 - 3.45)/(6 - 1.5)
\n" ); document.write( "m = 6.75/4.5 = 1.5\r
\n" ); document.write( "\n" ); document.write( "We have then \r
\n" ); document.write( "\n" ); document.write( "1.) y = 1.5*x + b. \r
\n" ); document.write( "\n" ); document.write( "Since the line passes through the point (6,10.2) when x = 6, y = 10.2. Substituting these values in 1.) we have: \r
\n" ); document.write( "\n" ); document.write( "10.2 = 1.5*6 + b\r
\n" ); document.write( "\n" ); document.write( "10.2 = 9 + b
\n" ); document.write( "b = 1.2\r
\n" ); document.write( "\n" ); document.write( "The equation of the line is then \r
\n" ); document.write( "\n" ); document.write( "2.) y = 1.5*x + 1.2\r
\n" ); document.write( "\n" ); document.write( "To find x for the third point on the line we substitute 2.85 for y in 2.):\r
\n" ); document.write( "\n" ); document.write( "2.85 = 1.5*x + 1.2
\n" ); document.write( "1.5*x = 2.85 - 1.2
\n" ); document.write( "1.5*x = 1.65
\n" ); document.write( "x = 1.65/1.5 = ?\r
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