document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=306870>Question 306870</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write the equation of a line that is perpendicular to the given line and that passes through the given point:\r<BR>\n" );
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document.write( "y=2/3x+9;(-6,5) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #219547 by </B><A HREF=/tutors/aboutme.mpl?userid=texttutoring><B>texttutoring(324)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=texttutoring><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=texttutoring><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=219547\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perpendicular lines have slopes that are negative reciprocals of each other.\r<BR>\n" );
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document.write( "The original line has a slope of m=2/3, so a line perpendicular to it will have a slope of m=-3/2\r<BR>\n" );
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document.write( "You know that the second line passes through (-6,5), so this tells us that x=-6, and y=5. Use y=mx+b, the equation of a line, to solve for b:\r<BR>\n" );
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document.write( "y=mx+b<BR>\n" );
document.write( "5=(-3/2)(-6) + b<BR>\n" );
document.write( "5 = 18/2 + b<BR>\n" );
document.write( "5 = 9 + b<BR>\n" );
document.write( "b = -4\r<BR>\n" );
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document.write( "The equation of the perpendicular line is y=(-3/2)x -4 </SPAN>\n" );
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