document.write( "Question 306865: I need help on a logarithm problem.\r
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document.write( "I need to Solve for X.\r
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document.write( "2ln(x)-ln(x+8/3)= ln(6) \n" );
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Algebra.Com's Answer #219542 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! 2ln(x)-ln((x+8)/3)= ln(6) \n" ); document.write( "ln(x^2)-ln((x+8)/3)= ln(6) \n" ); document.write( "ln(x^2)/((x+8)/3)= ln(6) \n" ); document.write( "(x^2)/((x+8)/3)= 6 \n" ); document.write( "(x^2) = 6((x+8)/3) \n" ); document.write( "(x^2) = 2(x+8) \n" ); document.write( "(x^2) = 2x+16 \n" ); document.write( "x^2-2x-16 = 0 \n" ); document.write( ". \n" ); document.write( "Solve by applying the quadratic formula. Doing so yields: \n" ); document.write( "x = {5.123, -3.123} \n" ); document.write( "Toss out the negative solution (extraneous) leaving: \n" ); document.write( "x = 5.123 \n" ); document.write( ". \n" ); document.write( "Details of quadratic formula follows: \n" ); document.write( "
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