document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=306812>Question 306812</A>: <I><SPAN STYLE=\"word-break: break-all;\"> On a separate sheet of paper, sketch each angle in standard position. Use a right triangle to find the exact values of the cosine and sine of the angle.\r<BR>\n" );
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document.write( "1. 45° </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #219540 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=219540\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We are in quadrant 1 because the angle given is positive.\r<BR>\n" );
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document.write( "Drop a perpendicular line from the terminal side of the angle creating a right triangle.\r<BR>\n" );
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document.write( "At the origin, we know that the angle is 45 degrees as given. When we drop a line from the terminal to the x-axis, we make 90 degrees where the line that is dropped meets the x-axis.  This means the we have a 45-45-90 degree right triangle.\r<BR>\n" );
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document.write( "This tells me, from the unit circle that you should memorize (it will make your entire trig journey so much easier) that the value of the hypotenuse is 2 and the two legs of the right triangle are square root 2.\r<BR>\n" );
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document.write( "sine = opposite side/hypotense\r<BR>\n" );
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document.write( "Then sine = sqrt{2}/2\r<BR>\n" );
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document.write( "cosine = adjacent side/hypotenuse\r<BR>\n" );
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document.write( "Then cosine = sqrt{2}/2\r<BR>\n" );
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document.write( " </SPAN>\n" );
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