document.write( "Question 306811: For questions 1-4, you draw a letter from the group below. After drawing the first letter, you replace it and draw another letter. Find each probability. \r
\n" ); document.write( "\n" ); document.write( "SUCCESS\r
\n" ); document.write( "\n" ); document.write( "p(vowel, then S)\r
\n" ); document.write( "\n" ); document.write( "P(c, Then E)\r
\n" ); document.write( "\n" ); document.write( "P(U, then consonant)\r
\n" ); document.write( "\n" ); document.write( "P(vowel, then C)
\n" ); document.write( "

Algebra.Com's Answer #219536 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "2 vowels
\n" ); document.write( "5 consonants
\n" ); document.write( "3 S
\n" ); document.write( "1 U
\n" ); document.write( "2 C
\n" ); document.write( "1 E
\n" ); document.write( "7 letters total
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "P(vowel)=2/7
\n" ); document.write( "P(S)=3/7
\n" ); document.write( "P(vowel,S)=(2/7)(3/7)=6/49
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "P(C)=2/7
\n" ); document.write( "P(E)=1/7
\n" ); document.write( "P(C,E)=(2/7)(1/7)=2/49
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "P(U)=1/7
\n" ); document.write( "P(consonant)=5/7
\n" ); document.write( "P(U,consonant)=(1/7)(5/7)=5/49
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "P(vowel)=2/7
\n" ); document.write( "P(C)=2/7
\n" ); document.write( "P(vowel,C)=(2/7)(2/7)=4/49
\n" ); document.write( "
\n" );