document.write( "Question 306854: I am very confused on how to find the vertex and points of a Parabola then when i graph it, the parabola always has a straight line on one side. How am I supposed to solve and graph 2x^2-13x-7=0? \n" ); document.write( "
Algebra.Com's Answer #219531 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
First complete the square to get to vertex form,
\n" ); document.write( "\"2x%5E2-13x-7=0\"
\n" ); document.write( "\"2%28x%5E2-%2813%2F2%29x%29-7=0\"
\n" ); document.write( "To complete the square, take (1/2) of the x-coefficient, square it, and then add it to both sides.
\n" ); document.write( "Since this is going on inside the parenthese, make sure to multiply by 2 to add the right hand value.
\n" ); document.write( "\"%281%2F2%29%2813%2F2%29=13%2F4\"
\n" ); document.write( "\"%2813%2F4%29%5E2=169%2F16\"
\n" ); document.write( "\"2%28x%5E2-%2813%2F2%29x%2B169%2F16%29-7=2%28169%2F16%29\"
\n" ); document.write( "\"2%28x-%2813%2F4%29%29%5E2-7=169%2F8%29\"
\n" ); document.write( "\"2%28x-%2813%2F4%29%29%5E2-56%2F8-169%2F8=0%29\"
\n" ); document.write( "\"2%28x-%2813%2F4%29%29%5E2-56%2F8-169%2F8=0%29\"
\n" ); document.write( "\"2%28x-%2813%2F4%29%29%5E2-225%2F8=0%29\"
\n" ); document.write( "Now the equation is in vertex form.
\n" ); document.write( "The vertex is (\"13%2F4\",\"-225%2F8\")
\n" ); document.write( "The y-intercept, from the original equation is, -7.
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\n" ); document.write( "Straight line on one side, what does that mean?
\n" ); document.write( "The axis of symmetry makes a mirror of the graph.
\n" ); document.write( "So then
\n" ); document.write( "\"f%2813%2F4%2B1%29=f%2813%2F4-1%29\"
\n" ); document.write( "\"f%2813%2F4%2B2%29=f%2813%2F4-2%29\"
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\n" ); document.write( "So then you only have to solve for one of those y coordinates and you'll have both.
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