document.write( "Question 35858: find an equation of the elipse having the given points as foci and the given number as sum of focal radii.
\n" ); document.write( "(-9,0);(9,0);30
\n" ); document.write( "

Algebra.Com's Answer #21953 by venugopalramana(3286)\"\" \"About 
You can put this solution on YOUR website!
find an equation of the elipse having the given points as foci and the given number as sum of focal radii.
\n" ); document.write( "(-9,0);(9,0);30
\n" ); document.write( "PLEASE NOTE THAT SUM OF FOCAL RADII=LENGTH OF MAJOR AXIS =2A =30....HENCE A=15
\n" ); document.write( "SEE THE FOLLOWING AND TRY.IF STILL IN DIFFICULTY
\n" ); document.write( "PLEASE COME BACK
\n" ); document.write( "---------------------------------------------------------------------------
\n" ); document.write( "Linear_Algebra/30362: Question: Find the equation of
\n" ); document.write( "the ellipse whose center is (5,-3) that has a vertex
\n" ); document.write( "at 13,-3) and a minor axis of lenght 10.
\n" ); document.write( "POssible Answers:
\n" ); document.write( "(A) (x-5)^2/64 + (y+3)^2/25 = 1
\n" ); document.write( "(B) (x+5)^2/64 + (y-3)^2/25 = 1
\n" ); document.write( "(C) x^2/64 + y^2/25 = 1
\n" ); document.write( "(D) none of these
\n" ); document.write( "1 solutions
\n" ); document.write( "Answer 17014 by venugopalramana(1167) About Me on
\n" ); document.write( "2006-03-15 11:21:03 (Show Source):
\n" ); document.write( "SEE THE FOLLOWING AND TRY..IF STILL IN DIFFICULTY
\n" ); document.write( "PLEASE COME BACK...
\n" ); document.write( "OK I WORKED IT OUT FOR YOU NOW
\n" ); document.write( "I TOLD YOU EQN IS
\n" ); document.write( "(X-H)^2/A^2 + (Y-K)^2/B^2 =1
\n" ); document.write( "WHERE H,K IS CENTRE...SO H=5 AND K=-3 AS CENTRE IS
\n" ); document.write( "GIVEN AS (5,-3)....NOW VERTEX IS (13,-3)...IT LIES ON
\n" ); document.write( "ELLIPSE..SO IT SATISFIES THE EQN
\n" ); document.write( "(13-5)^2/A^2 +(-3+3)^2/B^2 =1
\n" ); document.write( "HENCE A^2=64...OR A=8
\n" ); document.write( "MINOR AXIS =10=2B...HENCE B=5..SO EQN.S
\n" ); document.write( "(X-H)^2/64 + (Y+3)^2/25 =1
\n" ); document.write( "THAT IS A IS CORRECT.\r
\n" ); document.write( "\n" ); document.write( "Can you help me write an equation for an ellipse with
\n" ); document.write( "a major axis with endpoints of (0,8), and (0,-8) with
\n" ); document.write( "foci of (0,5) and (0,-5)?
\n" ); document.write( "1 solutions
\n" ); document.write( "--------------------------------------------------------------------------------
\n" ); document.write( "Answer 16810 by venugopalramana(1120) on 2006-03-13
\n" ); document.write( "11:19:12 (Show Source):
\n" ); document.write( "Can you help me write an equation for an ellipse with
\n" ); document.write( "a major axis with endpoints of (0,8), and (0,-8) with
\n" ); document.write( "foci of (0,5) and (0,-5)?
\n" ); document.write( "THIS SHOWS THAT X AXIS IS THE MAJOR AXIS
\n" ); document.write( "STANDARD EQN.OF ELLIPSE IS
\n" ); document.write( "(X-H)^2/A^2 +(Y-K)^2/B^2=1
\n" ); document.write( "CENTRE IS (H,K)..AS PER THE PROBLEM H=K=0 AS CENTRE OF
\n" ); document.write( "ELLIPSE IS AT (0,0)..SINCE major axis with endpoints
\n" ); document.write( "ARE (0,8), and (0,-8)
\n" ); document.write( "WHERE MAJOR AXIS =2A=8+8=16...SO A=8..SINCE major axis
\n" ); document.write( "with endpoints ARE (0,8), and (0,-8)
\n" ); document.write( "FOCI ARE GIVEN BY
\n" ); document.write( "AE,0 AND -AE,0...SO AE =5...SO E=5/A=5/8
\n" ); document.write( "BUT E=SQRT{(A^2-B^2)/A^2}=5/8...SQUARING
\n" ); document.write( "25/64=(A^2-B^2)/A^2=1-B^2/A^2
\n" ); document.write( "B^2/64=1-25/64=49/64
\n" ); document.write( "B^2=49
\n" ); document.write( "B=7
\n" ); document.write( "HENCE EQN. OF ELLIPSE IS
\n" ); document.write( "X^2/64 + Y^2/49 = 1\r
\n" ); document.write( "\n" ); document.write( "Quadratic-relations-and-conic-sections/30009: Can you
\n" ); document.write( "help me write an equation for an ellipse with a major
\n" ); document.write( "axis with endpoints of (0,8), and (0,-8) with foci of
\n" ); document.write( "(0,5) and (0,-5)?\r
\n" ); document.write( "\n" ); document.write( "1 solutions
\n" ); document.write( "Answer 16810 by venugopalramana(1167) About Me on
\n" ); document.write( "2006-03-13 11:19:12 (Show Source):
\n" ); document.write( "Can you help me write an equation for an ellipse with
\n" ); document.write( "a major axis with endpoints of (0,8), and (0,-8) with
\n" ); document.write( "foci of (0,5) and (0,-5)?
\n" ); document.write( "THIS SHOWS THAT X AXIS IS THE MAJOR AXIS
\n" ); document.write( "STANDARD EQN.OF ELLIPSE IS
\n" ); document.write( "(X-H)^2/A^2 +(Y-K)^2/B^2=1
\n" ); document.write( "CENTRE IS (H,K)..AS PER THE PROBLEM H=K=0 AS CENTRE OF
\n" ); document.write( "ELLIPSE IS AT (0,0)..SINCE major axis with endpoints
\n" ); document.write( "ARE (0,8), and (0,-8)
\n" ); document.write( "WHERE MAJOR AXIS =2A=8+8=16...SO A=8..SINCE major axis
\n" ); document.write( "with endpoints ARE (0,8), and (0,-8)
\n" ); document.write( "FOCI ARE GIVEN BY
\n" ); document.write( "AE,0 AND -AE,0...SO AE =5...SO E=5/A=5/8
\n" ); document.write( "BUT E=SQRT{(A^2-B^2)/A^2}=5/8...SQUARING
\n" ); document.write( "25/64=(A^2-B^2)/A^2=1-B^2/A^2
\n" ); document.write( "B^2/64=1-25/64=49/64
\n" ); document.write( "B^2=49
\n" ); document.write( "B=7
\n" ); document.write( "HENCE EQN. OF ELLIPSE IS
\n" ); document.write( "X^2/64 + Y^2/49 = 1
\n" ); document.write( "
\n" );