document.write( "Question 35863: ln(1/x) = 2 \n" ); document.write( "
Algebra.Com's Answer #21949 by AnlytcPhil(1806)\"\" \"About 
You can put this solution on YOUR website!
                            ln(1/x) = 2\r\n" );
document.write( "\r\n" );
document.write( "On the left side, use this rule of logarithms:\r\n" );
document.write( "\r\n" );
document.write( "  ln(A/B) = ln(A) - ln(B)\r\n" );
document.write( "\r\n" );
document.write( "with A = 1 and B = x\r\n" );
document.write( "\r\n" );
document.write( "                      ln(1) - ln(x) = 2\r\n" );
document.write( "\r\n" );
document.write( "                          0 - ln(x) = 2 \r\n" );
document.write( "\r\n" );
document.write( "                             -ln(x) = 2\r\n" );
document.write( "\r\n" );
document.write( "Multiply or divide thru by -1\r\n" );
document.write( "\r\n" );
document.write( "                              ln(x) = -2\r\n" );
document.write( "\r\n" );
document.write( "Use this equation-exchange rule:  The equation\r\n" );
document.write( "\r\n" );
document.write( " ln(A) = B \r\n" );
document.write( "\r\n" );
document.write( "is equivalent to and may be replaced by the equation\r\n" );
document.write( "\r\n" );
document.write( "    A = eB.\r\n" );
document.write( "\r\n" );
document.write( "with A = 2 and B = -2 \r\n" );
document.write( " \r\n" );
document.write( "So equation\r\n" );
document.write( "\r\n" );
document.write( "                             ln(x) = -2 \r\n" );
document.write( "\r\n" );
document.write( "becomes equation\r\n" );
document.write( "\r\n" );
document.write( "                                 x = e-2,\r\n" );
document.write( "\r\n" );
document.write( "or by calculator,                x = .1353352832\r\n" );
document.write( "\r\n" );
document.write( "Edwin McCravy\r\n" );
document.write( "AnlytcPhil@aol.com
\n" ); document.write( "
\n" );