document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=306787>Question 306787</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find sec(2/3pi). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #219483 by </B><A HREF=/tutors/aboutme.mpl?userid=texttutoring><B>texttutoring(324)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=texttutoring><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=texttutoring><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=219483\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Draw the unit circle.\r<BR>\n" );
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document.write( "2pi/3 radians is equivalent to 120 degrees.\r<BR>\n" );
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document.write( "This means that your terminal arm will create an angle of 60 degrees with the x axis, in the second quadrant.\r<BR>\n" );
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document.write( "Secant = 1/Cosine\r<BR>\n" );
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document.write( "The value of Cos(120) can then be found from the 30-60-90 triangle drawn in the second quadrant, as 120 degrees has a reference angle of 60 degrees. (This would probably make more sense with a picture, but I don't know how to draw one on here.)\r<BR>\n" );
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document.write( "Cos(120)=-1/2\r<BR>\n" );
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document.write( "Sec(120) = -2/1 = -2\r<BR>\n" );
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document.write( "Let me know if you need any clarifications. </SPAN>\n" );
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