document.write( "Question 306672: A tobacco dealer mixed 12 lbs of one grade of tobacco with 10 lbs of another grade to obtain a blend worth $54. He then made a second blend worth $61 by mixing 8 lbs of the first grade and 15 lbs of the second grade. Find the price per lb in each grade.\r
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document.write( "choices:
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document.write( "a:) $2 and $3
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document.write( "a:) $2 and $4
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document.write( "a:) $1 and $2
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document.write( "a:) $1 and $3 \n" );
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Algebra.Com's Answer #219432 by mananth(16946)![]() ![]() You can put this solution on YOUR website! A tobacco dealer mixed 12 lbs of one grade of tobacco with 10 lbs of another grade to obtain a blend worth $54. He then made a second blend worth $61 by mixing 8 lbs of the first grade and 15 lbs of the second grade. Find the price per lb in each grade.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let blend one price be $x \n" ); document.write( "Let blend 2 price be y\r \n" ); document.write( "\n" ); document.write( "12x+10y=54\r \n" ); document.write( "\n" ); document.write( "8x+15y=61\r \n" ); document.write( "\n" ); document.write( "2(12x+10y) - 3(8x+15y)= 2*54 - 3*61\r \n" ); document.write( "\n" ); document.write( "24x+20y-24x-45y= -75\r \n" ); document.write( "\n" ); document.write( "-25y=-75 \n" ); document.write( "y=3.... $3 for the secon blend \n" ); document.write( "plug the value of y in equation 12x+10y=24 \n" ); document.write( "x=2\r \n" ); document.write( "\n" ); document.write( "$2, $3 is the price \n" ); document.write( " |