Algebra.Com's Answer #219414 by ichudov(507)![\"\"](\"/images/stars/stars-10.gif\")  You can put this solution on YOUR website! This looks so complicated and intimidating, that the first instinct is to give up. \r \n" ); document.write( "\n" ); document.write( "The second thought that you should always have is that such problems always have simple, easy solutions that school students can easily figure out. \r \n" ); document.write( "\n" ); document.write( "What you know is that if the roots are integer, then the constant part 9, is their product. About the only thing that 9 is divisible by, is 3 and 1. Simple substitution reveals that both 3 and 1 are indeed roots of this polynomial. \r \n" ); document.write( "\n" ); document.write( "Divide the polynomial by (x-1) and then by (x-1) and you get a simple quadratic equation, which you can easily solve. Give it a try. \n" ); document.write( " |