document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=306638>Question 306638</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this. The product of two consecutive integers is equal to ten times the smaller integer minus eight. Find the integers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #219412 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=219412\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the numbers be x & x+1\r<BR>\n" );
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document.write( "product of both = x(x+1)\r<BR>\n" );
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document.write( "x(x+1)= 10x-8\r<BR>\n" );
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document.write( "x^2+x=10x-8\r<BR>\n" );
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document.write( "x^2-8x+9=0\r<BR>\n" );
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document.write( "x^2-9x+x-9=0\r<BR>\n" );
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document.write( "x(x-9)+1(x-9)=0\r<BR>\n" );
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document.write( "(x-9)(x+1)=0\r<BR>\n" );
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document.write( "x= 9 OR -1\r<BR>\n" );
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document.write( " </SPAN>\n" );
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