document.write( "Question 306590: With a tailwind, an airlplane can fly 1440 km in 2.5 hours. On the return flight with the same wind and flying distance the flight takes 3 h. Find the rate of the plane and the rate of the wind. Help please! \n" ); document.write( "

Algebra.Com's Answer #219386 by mananth(16946) $\"\"$ $\"About$

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With a tailwind, an airlplane can fly 1440 km in 2.5 hours. On the return flight with the same wind and flying distance the flight takes 3 h. Find the rate of the plane and the rate of the wind. Help please!\r
\n" ); document.write( "\n" ); document.write( "let the tail wind be xmph\r
\n" ); document.write( "\n" ); document.write( "let the airplane speed be y kmph\r
\n" ); document.write( "\n" ); document.write( "with tail wind the speed will be x+y kmph\r
\n" ); document.write( "\n" ); document.write( "distance traveled =1440 km\r
\n" ); document.write( "\n" ); document.write( "time taken = 1440 / x+y = 2.5\r
\n" ); document.write( "\n" ); document.write( "1440 = 2.5x+2.5y
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\n" ); document.write( "Against wind the airplane speed will be y-x\r
\n" ); document.write( "\n" ); document.write( "time taken = 1440/ y-x = 3\r
\n" ); document.write( "\n" ); document.write( "1440 = 3y-3x\r
\n" ); document.write( "\n" ); document.write( "3(2.5x+2.5y)+2.5(3y-3x) =3*1440 + 2.5*1440\r
\n" ); document.write( "\n" ); document.write( "7.5x +7.5y+7.5y-7.5x=7920\r
\n" ); document.write( "\n" ); document.write( "15y= 7920
\n" ); document.write( "y=528 kmph airplane speed\r
\n" ); document.write( "\n" ); document.write( "x= 48 kmph wind speed\r
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