document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=306509>Question 306509</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist has one solution that is 40% alcohol and another that is 55% alcohol. How much of each must she use to make 15 liters of solution that is 50% alcohol? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #219381 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=219381\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A chemist has one solution that is 40% alcohol and another that is 55% alcohol. How much of each must she use to make 15 liters of solution that is 50% alcohol?\r<BR>\n" );
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document.write( "Let x be the amount of 40% alcohol and y the amount of 55% alcohol. Then we have:\r<BR>\n" );
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document.write( "1.) x + y = 15 and<BR>\n" );
document.write( "2.) .40x + .55y = .50*15\r<BR>\n" );
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document.write( "From 1.) we know that x = 15-y. Substituting 15-y for x in 2.) gives us:\r<BR>\n" );
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document.write( ".40*(15-y) + .55*y = 7.5<BR>\n" );
document.write( "6 - .4y + .55y = 7.5<BR>\n" );
document.write( ".15y = 1.5<BR>\n" );
document.write( "y = 10\r<BR>\n" );
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document.write( "Substituting 10 for y in equation 1.) we have x + 10 = 15, so x =5.<BR>\n" );
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