document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=306552>Question 306552</A>: <I><SPAN STYLE=\"word-break: break-all;\"> It is necessary to have a 40% antifreeze solution in the radiator of a certain car. The radiator now<BR>\n" );
document.write( "has 50 liters of 20% solution. How many liters of this should be drained and replaced with 100%<BR>\n" );
document.write( "antifreeze to get the desired strength? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #219371 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=219371\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+.20(50-x)=.40*50<BR>\n" );
document.write( "x=10-.20x=20<BR>\n" );
document.write( ".8x=20-10<BR>\n" );
document.write( ".8x=10<BR>\n" );
document.write( "x=10/.8<BR>\n" );
document.write( "x=12.5 liters need to be drained & filled with 100% antifreeze.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "12.5+.20(50-12.5)=.40*50<BR>\n" );
document.write( "12.5+.20*37.5=20<BR>\n" );
document.write( "12.5+7.5=20<BR>\n" );
document.write( "20=20 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );